125 lines
3.2 KiB
C
125 lines
3.2 KiB
C
|
#include "jemalloc/internal/jemalloc_preamble.h"
|
||
|
#include "jemalloc/internal/jemalloc_internal_includes.h"
|
||
|
|
||
|
#include "jemalloc/internal/fxp.h"
|
||
|
|
||
|
static bool
|
||
|
fxp_isdigit(char c) {
|
||
|
return '0' <= c && c <= '9';
|
||
|
}
|
||
|
|
||
|
bool
|
||
|
fxp_parse(fxp_t *result, const char *str, char **end) {
|
||
|
/*
|
||
|
* Using malloc_strtoumax in this method isn't as handy as you might
|
||
|
* expect (I tried). In the fractional part, significant leading zeros
|
||
|
* mean that you still need to do your own parsing, now with trickier
|
||
|
* math. In the integer part, the casting (uintmax_t to uint32_t)
|
||
|
* forces more reasoning about bounds than just checking for overflow as
|
||
|
* we parse.
|
||
|
*/
|
||
|
uint32_t integer_part = 0;
|
||
|
|
||
|
const char *cur = str;
|
||
|
|
||
|
/* The string must start with a digit or a decimal point. */
|
||
|
if (*cur != '.' && !fxp_isdigit(*cur)) {
|
||
|
return true;
|
||
|
}
|
||
|
|
||
|
while ('0' <= *cur && *cur <= '9') {
|
||
|
integer_part *= 10;
|
||
|
integer_part += *cur - '0';
|
||
|
if (integer_part >= (1U << 16)) {
|
||
|
return true;
|
||
|
}
|
||
|
cur++;
|
||
|
}
|
||
|
|
||
|
/*
|
||
|
* We've parsed all digits at the beginning of the string, without
|
||
|
* overflow. Either we're done, or there's a fractional part.
|
||
|
*/
|
||
|
if (*cur != '.') {
|
||
|
*result = (integer_part << 16);
|
||
|
if (end != NULL) {
|
||
|
*end = (char *)cur;
|
||
|
}
|
||
|
return false;
|
||
|
}
|
||
|
|
||
|
/* There's a fractional part. */
|
||
|
cur++;
|
||
|
if (!fxp_isdigit(*cur)) {
|
||
|
/* Shouldn't end on the decimal point. */
|
||
|
return true;
|
||
|
}
|
||
|
|
||
|
/*
|
||
|
* We use a lot of precision for the fractional part, even though we'll
|
||
|
* discard most of it; this lets us get exact values for the important
|
||
|
* special case where the denominator is a small power of 2 (for
|
||
|
* instance, 1/512 == 0.001953125 is exactly representable even with
|
||
|
* only 16 bits of fractional precision). We need to left-shift by 16
|
||
|
* before dividing so we pick the number of digits to be
|
||
|
* floor(log(2**48)) = 14.
|
||
|
*/
|
||
|
uint64_t fractional_part = 0;
|
||
|
uint64_t frac_div = 1;
|
||
|
for (int i = 0; i < FXP_FRACTIONAL_PART_DIGITS; i++) {
|
||
|
fractional_part *= 10;
|
||
|
frac_div *= 10;
|
||
|
if (fxp_isdigit(*cur)) {
|
||
|
fractional_part += *cur - '0';
|
||
|
cur++;
|
||
|
}
|
||
|
}
|
||
|
/*
|
||
|
* We only parse the first maxdigits characters, but we can still ignore
|
||
|
* any digits after that.
|
||
|
*/
|
||
|
while (fxp_isdigit(*cur)) {
|
||
|
cur++;
|
||
|
}
|
||
|
|
||
|
assert(fractional_part < frac_div);
|
||
|
uint32_t fractional_repr = (uint32_t)(
|
||
|
(fractional_part << 16) / frac_div);
|
||
|
|
||
|
/* Success! */
|
||
|
*result = (integer_part << 16) + fractional_repr;
|
||
|
if (end != NULL) {
|
||
|
*end = (char *)cur;
|
||
|
}
|
||
|
return false;
|
||
|
}
|
||
|
|
||
|
void
|
||
|
fxp_print(fxp_t a, char buf[FXP_BUF_SIZE]) {
|
||
|
uint32_t integer_part = fxp_round_down(a);
|
||
|
uint32_t fractional_part = (a & ((1U << 16) - 1));
|
||
|
|
||
|
int leading_fraction_zeros = 0;
|
||
|
uint64_t fraction_digits = fractional_part;
|
||
|
for (int i = 0; i < FXP_FRACTIONAL_PART_DIGITS; i++) {
|
||
|
if (fraction_digits < (1U << 16)
|
||
|
&& fraction_digits * 10 >= (1U << 16)) {
|
||
|
leading_fraction_zeros = i;
|
||
|
}
|
||
|
fraction_digits *= 10;
|
||
|
}
|
||
|
fraction_digits >>= 16;
|
||
|
while (fraction_digits > 0 && fraction_digits % 10 == 0) {
|
||
|
fraction_digits /= 10;
|
||
|
}
|
||
|
|
||
|
size_t printed = malloc_snprintf(buf, FXP_BUF_SIZE, "%"FMTu32".",
|
||
|
integer_part);
|
||
|
for (int i = 0; i < leading_fraction_zeros; i++) {
|
||
|
buf[printed] = '0';
|
||
|
printed++;
|
||
|
}
|
||
|
malloc_snprintf(&buf[printed], FXP_BUF_SIZE - printed, "%"FMTu64,
|
||
|
fraction_digits);
|
||
|
}
|