753bbf1849
This is often what we really care about. It's not easy to do the division mentally in all cases.
61 lines
1.6 KiB
C
61 lines
1.6 KiB
C
static inline void
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time_func(timedelta_t *timer, uint64_t nwarmup, uint64_t niter,
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void (*func)(void)) {
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uint64_t i;
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for (i = 0; i < nwarmup; i++) {
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func();
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}
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timer_start(timer);
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for (i = 0; i < niter; i++) {
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func();
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}
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timer_stop(timer);
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}
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#define FMT_NSECS_BUF_SIZE 100
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/* Print nanoseconds / iter into the buffer "buf". */
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static inline void
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fmt_nsecs(uint64_t usec, uint64_t iters, char *buf) {
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uint64_t nsec = usec * 1000;
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/* We'll display 3 digits after the decimal point. */
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uint64_t nsec1000 = nsec * 1000;
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uint64_t nsecs_per_iter1000 = nsec1000 / iters;
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uint64_t intpart = nsecs_per_iter1000 / 1000;
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uint64_t fracpart = nsecs_per_iter1000 % 1000;
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malloc_snprintf(buf, FMT_NSECS_BUF_SIZE, "%"FMTu64".%03"FMTu64, intpart,
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fracpart);
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}
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static inline void
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compare_funcs(uint64_t nwarmup, uint64_t niter, const char *name_a,
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void (*func_a), const char *name_b, void (*func_b)) {
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timedelta_t timer_a, timer_b;
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char ratio_buf[6];
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void *p;
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p = mallocx(1, 0);
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if (p == NULL) {
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test_fail("Unexpected mallocx() failure");
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return;
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}
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time_func(&timer_a, nwarmup, niter, func_a);
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time_func(&timer_b, nwarmup, niter, func_b);
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uint64_t usec_a = timer_usec(&timer_a);
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char buf_a[FMT_NSECS_BUF_SIZE];
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fmt_nsecs(usec_a, niter, buf_a);
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uint64_t usec_b = timer_usec(&timer_b);
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char buf_b[FMT_NSECS_BUF_SIZE];
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fmt_nsecs(usec_b, niter, buf_b);
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timer_ratio(&timer_a, &timer_b, ratio_buf, sizeof(ratio_buf));
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malloc_printf("%"FMTu64" iterations, %s=%"FMTu64"us (%s ns/iter), "
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"%s=%"FMTu64"us (%s ns/iter), ratio=1:%s\n",
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niter, name_a, usec_a, buf_a, name_b, usec_b, buf_b, ratio_buf);
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dallocx(p, 0);
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}
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